STPS1L30 Datasheet 30 V, 1 A low drop power Schottky rectifier Features Very low forward voltage drop for less power dissipation Surface mount miniature packages Avalanche rated ECOPACK2 compliant Applications Cordless appliance SSD Battery charger Telecom power DC / DC converter Description Schottky rectifiers designed for high frequency miniature switched mode power supplies such as adaptors and on board DC/DC converters. Packaged in SMA, SMA Flat Notch or SMB, the STPS1L30 is ideal for use in parallel with MOSFETs in synchronous rectification. Product status STPS1L30 Product summary Symbol Value I F(AV) 1 A V 30 V RRM T 150 C j(max.) V 0.26 V F(typ.) DS1243 - Rev 8 - September 2019 www.st.com For further information contact your local STMicroelectronics sales office.STPS1L30 Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values at 25 C, unless otherwise specified) Symbol Parameter Value Unit V Repetitive peak reverse voltage 30 V RRM I Forward rms current 10 A F(RMS) T = 135 C SMA L I T = 140 C Average forward current, = 0.5, square wave SMA Flat Notch 1 A F(AV) L SMB T = 140 C L SMA 75 I t = 10 ms sinusoidal FSM Surge non repetitive forward current SMA Flat Notch p 90 A SMB 75 P t = 10 s, T = 125 C Repetitive peak avalanche power 110 W ARM p j T Storage temperature range -65 to +150 C stg (1) T +150 C j Maximum operating junction temperature 1. (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 2. Thermal resistance parameter Symbol Parameter Max. value Unit SMA 30 R Junction to lead SMA Flat Notch 20 C/W th(j-l) SMB 25 For more information, please refer to the following application note : AN5088 : Rectifiers thermal management, handling and mounting recommendations Table 3. Static electrical characteristics Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 200 A j (1) I Reverse leakage current V = V R RRM R T = 100 C - 6 15 mA j T = 25 C - 0.395 j I = 1 A F T = 125 C - 0.260 0.300 j (1) V Forward voltage drop V F T = 25 C - 0.445 j I = 2 A F T = 125 C - 0.325 0.375 j 1. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses, use the following equation: 2 P = 0.225x I + 0.075 x I F(AV) F (RMS) DS1243 - Rev 8 page 2/15