STBR6008-Y Datasheet Automotive 800 V, 60 A bridge rectifier diode Features A K AEC-Q101 qualified Ultra low conduction losses Ultra-low reverse losses High junction temperature capability (+175 C) A V guaranteed from -40 to +175 C K RRM PPAP capable DO-247 ECOPACK2 compliant Applications On board charger (OBC) Charging stations Bridge function Description The high quality design of this diode has produced a device with consistently reproducible characteristics and intrinsic ruggedness. These characteristics make it ideal for heavy duty applications that demand long term reliability like automotive applications. Product status link Thanks to its ultra-low conduction losses, the STBR6008-Y is especially suitable for use as input bridge diode in battery chargers and charging stations. STBR6008-Y Product summary Symbol Value I F(AV) 60 A V 800 V RRM T -40 to +175 C j V (typ.) 1.00 V F DS13045 - Rev 1 - June 2019 www.st.com For further information contact your local STMicroelectronics sales office.STBR6008-Y Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values at 25 C, unless otherwise specified) Symbol Parameter Value Unit V T = -40 C to +175 C Repetitive peak reverse voltage 800 V RRM j V t = 10 ms square Non-repetitive surge reverse voltage 900 V RSM p I Forward rms current 90 A F(RMS) I T = 160 C, = 0.5 square wave Average forward current 60 A F(AV) C I Surge non repetitive forward current t = 10 ms sinusoidal 500 A FSM p T Storage temperature range -65 to +175 C stg T Operating junction temperature -40 to +175 C j Table 2. Thermal parameters Typ. Symbol Parameter Unit value R Junction to case 0.20 C/W th(j-c) For more information, please refer to the following application note : AN5088 : Rectifiers thermal management, handling and mounting recommendations Table 3. Static electrical characteristics Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 5 j I V = V R Reverse leakage current R RRM A T = 150 C - 25 250 j T = 25 C - 1.00 1.10 j V I = 60 A Forward voltage drop V F F T = 150 C - 0.88 0.97 j 1. Pulse test: t = 5 ms, < 2% p 2. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses, use the following equation: 2 P = 0.75 x I + 0.0036 x I F(AV) F (RMS) For more information, please refer to the following application notes related to the power losses: AN604: Calculation of conduction losses in a power rectifier AN4021: Calculation of reverse losses in a power diode DS13045 - Rev 1 page 2/9